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04 Jun 2024

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If f(0)=4 and f(x+1) = 3f(x) The fibonacci sequence is f(n) = f(n-1) + f(n If f(1) = 1 and f(n+1) = 2f(n) + 1 if n≥1, then f(n) is equal to 2^n+1b

Solved variation on #53-3.] find f(2), f(3), f(4), and f(5)

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